0 Ответ от Agalanim
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RockWare LogPlot 7.4.113.119 cracked

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1 Ответ от Shalis
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2 Ответ от Nirad
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Download LogPlot 7.4.79.105

These plots help us to see large range quantities in a small plane. New downloads are added to the member section daily and we now have 421, 377 downloads for our members, including: TV, Movies, Software, Games, Music and More. RockWorks16 is the latest version of RockWare's flagship software program. Please help us by submitting a rating. LogPlot effectively generates a curve based on Log [f], but with tick marks indicating the values of the underlying function f. LogPlot makes exponentials appear as straight lines. Technology-enabling science of the computational universe. We use this information to help you open your files.

3 Ответ от Lajurus
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MATLAB Log Plot: Loglog and Everything You Need to Know
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4 Ответ от Bulanim
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Keygen download Logplot 7 Crack 318 - Ahsana Property Syariah

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Help with Plot, PlotRange

As an example I wanted some plots showing the majority of the mass of the integral of the following function is concentrated in a relatively small range.
x = 100 Plot[Sqrt[Sin[t]] Exp[-x*Sin[4 t]], {t, 0, Pi/2}, AspectRatio -> 1, PlotRange -> All]
So using x=100 I get a plot that's illustrative but at x=1000 I get nothing. No axis, no plot. So (naturally) I tried a LogPlot 
x = 1000 LogPlot[Sqrt[Sin[t]] Exp[-x*Sin[4 t]], {t, 0, Pi/2}, AspectRatio -> 1, PlotRange -> All]
but even then the vertical axis range will only go from 10-217 to 10207 using x=1,000 and I end up losing the majority of the mass of the function (values around 10434 when t is near 3Pi/8).
With the LogPlot am I just hitting the limits of the range of numbers Mathematica can handle? And using Plot is there a better way to control the vertical axis range other then "PlotRange All"?
Thanks.
submitted by tempmike to Mathematica

5 Ответ от Dorigas
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Here's how to tell when its going to dump

Its when the dots don't connect anymore.
I'm somewhat serious though. The validity of log linearity. is discussed here.
This google drive has the excel simple fit in it to look at.
Shameless plug of my theories? Maybe. But I want to know what you guys think - maybe its possible to extract a condition. We have 3 bubble pop examples, and all of them have "discontinuous dots" above the exponential fitted price point. That amounts to the rate of the change of the normalized the price (1/P)(ΔP/ day) being sufficiently high.
If you speak mathematica, you can mess with these more intricate models
Does it work?
submitted by AltoidNerd to BitcoinMarkets